The distance travelled by a falling body in the last second of its motion.
The correct answer for this problem is option (D).
The distance travelled by a falling body in the last second of its motion 56. For example, if a car travels 3 meters every second, it is covering an equal distance every second; the speed of the body is 3m/sec. Distance The first equation shows that, after one second, an object will have fallen a distance of 1/2 × 9. 8) A stone falls freely from rest, and the total distance covered by it in the last second of its motion equals the distance covered by it in the first three seconds of its motion. 126. 6 m/s (b) 39. Take the acceleration due to gravity 푔 = 9. 6 m/s 2) 39. Here is the typical freefall distance problem: A free-falling body without initial velocity passed 2/3 of its path at the last second of its fall. (g = 9. Then calculate the distance travelled at the last second. The velocity with which the body strikes the ground is (a) 19. Apr 22, 2023 · The distance travelled by a freely falling body in the last second of its free fall is equal to ha of the total displacement. Jul 21, 2023 · Step by step video solution for The distance travelled by a falling body in the last second of its motion, to that in the last but one second is 7: 5, the velocity with which body strikes the ground is by Physics experts to help you in doubts & scoring excellent marks in Class 11 exams. 2 m/s 3) 29. 8ms−2) is View Solution Q 4 Jun 5, 2025 · If the distance travelled by a freely falling body in the last but one second of its motion is 5 m, then the last second is: A body is allowed to fall from a height of 98 m before hitting the ground the distance travelled by it in the last second of motion (g = 9. 8 × 2 2 = 19. Jul 12, 2019 · The distance travelled by a falling body in the last second of its motion, to that in the last but one second is 7:5, the velocity with which body strikes the ground is A freely falling body, falling from a tower of heighth covers a distance h/2 in the last second of its motion The height of the tower is 10 ms^ (-2) ): View Solution The distance travelled by a body during last second of its upward journey is d when the body is projected with certain velocity vertically up. 2. 9 m/s from the top of a tower that is 457 meters high. View Solution A body is allowed to fall from a height of 98 m before hitting the ground the distance travelled by it in the last second of motion (g = 9. If an object fell 10 000 m to Earth, then the results of both equations differ by only 0. 8 m / s 2) 1. the velocity with which the body - 2420148… Hint: Equation of motion has the solution of this question. For the second part, we need to calculate the time of fall for a body that travels half its total path in the last second of its fall from rest. 08 %; however, if it During the last second of its free fall, a body covers half of the total distance travelled. Distance travelled by a stone falling freely from rest in the last second of its motion is equal to the distance travelled in first 3 seconds of its motion. Here h m hm as function of ϕ ϕ can be presented as If a freely falling body travels in the last second a distance equal to the distance travelled by i D. 1) 19. Find the total time taken by the body to reach the ground. The velocity with which the body strikes the ground is : (Given 9. Mar. Find the time for which the stone remains in the air and the total height from where the stone is dropped. The distance travelled by a freely falling body in the last second of its motion, to that in the last but one second is 7:5. 8ms−2) is The ratio of distance travelled by a body falling freely from rest in the last second of its motion to that in last but one second of its motion is 5:4. Calculate:i) the duration of the fallii) the approximate height from which the body falls. Jun 5, 2025 · If the distance travelled by a freely falling body in the last but one second of its motion is 5 m, then the last second is:The angle of projection of a particle is measured from the vertical axis as ϕ ϕ and the maximum height reached by the particle is h m hm. 4 m/s 4) 49 m/s Views: 5,610 students Updated on: Jan 3, 2025 The distance travelled by a falling body in the last second of its motion, to that in the last but one second is 7: 5, the velocity with which body strikes the ground is Aug 19, 2020 · Answer: The distance travelled by a falling body in the last second of its motion, to that in the last but one second is 7:5, the velocity with which body strikes the ground is. 3s 4s 5s 6s Derive an equation for the distance covered by a uniformly accelerated body in nth second of its motion. . Formula: s = u t + 1 2 g t 2 u is the initial velocity, t is the time, g is The correct answer is g(n−1/2 May 16, 2021 · Find an answer to your question the ratio of distance described by a body falling freely from rest in the last second of its motion to that in last but one seco… The ratio of distance travelled by a body falling freely from rest in the last second of its motion to that in last but one second of its motion is 5:4. 4 m/s (d) 49 m/s Nov 11, 2019 · My book states that the distance traveled by a particle thrown upward in the last second is independent of it's initial velocity because the the object travels the same distance as a freely falling The ratio of distance travelled by a body falling freely from rest in the last second of its motion to that in last but one second of its motion is 5:4. S=ut+ 1 2 a t 2 where, S is the distance and u is the initial speed of an object, a is the acceleration and t is time. Find the time of its travel. Note: It is advisable to students to understand and remember the formulas of Newton’s law motion as it is helpful in solving problems of these kinds. The time of its free fall is 2sec 2 2sec (2+ 2)sec (2− 2)sec If the ratio of distances travelled by freely falling body in the last and last but one second of its motion is 75. The distance travelled by a freely falling body in the last second of its motion, to that in the last but one second is 7:5, what is the velocity with which body strikes the ground? Sep 29, 2020 · The distance traveled by a falling body in the last second of its motion , to that in the last but one second is 7:5. The distance travelled by a falling body in the last second of its motion, compared to that in the last but one second, is 7:5. If the velocity of projection is doubled, the The ratio of the distance travelled by a falling body in the last second of its motion to that in the last but one second is 7:5, the velocity (in m/sec) with which body strikes the ground is…. 5K subscribers Join Aug 21, 2025 · The body is known to have uniform motion in a straight line if it travels an equal distance in per unit time. Oct 21, 2018 · The distance travelled by a freely falling body from rest in first 5 seconds of its motion is equal to the distance travelled in last second of its journey. Jan 8, 2025 · Explanation: To derive the equation for the distance covered by a uniformly accelerated body in the nth second of its motion, we use the equations of motion. On the other hand, the penultimate equation becomes grossly inaccurate at great distances. m. What is the velocity with which the body strikes the ground? Our free fall calculator can find the velocity of a falling object and the height it drops from. The velocity with which the body strikes the ground is: 1) 19. Hint: Apply the kinematic equation of motion, where you substitute the value of u is the initial velocity, t is the time, g is the acceleration of gravity. K. 6 m/s. 22, 2023 06:11 p. - The body is dropped from rest, so its initial velocity u = 0. After two seconds it will have fallen 1/2 × 9. The distance travelled by a body falling freely from rest in 2, 3 and 5 second of its motion are in the ratio the distance travelled by a falling body in the last second of its motion to that of the last but one second is 7:5, the velocity with which body strikes the ground is Submitted by Jeffrey B. Step by step The correct answer for this problem is option (D). Find the ratio of the distances travelled by a freely falling body in first, second and third second of its fall. But here the body is travelling in projectile motion which means it will suffer acceleration due to gravity. Determine the distance that the body covered in the last second before it struck the ground. We need to find the total time of travel, denoted as *t*. The time of its fall is Question Answers for Class 4 The distances covered by a freely falling body in its first, second, third, nth Seconds of its motion (A) forms an arithmetic progression (B) forms a geometric progression (C) do not form any well-defined series (D) forms a series corresponding to the difference of square root of the successive natural numbers. 8 m/s². Understanding the Motion: - A freely falling body is under constant acceleration due to gravity g. Jul 12, 2019 To calculate distance travelled at the last second. 1. A body travels half its total path in the last second of its fall from rest. To solve the problem, we need to find the time of descent t0 of a freely falling body, given that the distance traveled in the last second of its journey is equal to the distance traveled in the first 2 seconds. 9 m. Calculate the distance travelled for the first 3 seconds. The ratio of distance travelled by a body falling freely from rest in the last second of its motion to that in last but one second of its motion is 5:4. 8 × 1 2 = 4. Force is proportional to mass and acceleration. Ans: Hint: We can use the second equation of motion to calculate A body was projected vertically downwards at 66. Note: In such types of questions, sometimes students forget to consider the initial velocity of the object during free fall as zero. 6 m; and so on. Goyal 29. By the eqn of last second and just before of it we will get the distance travelled by it. The distance described by a falling body in the last second of its motion is to that described by it in its last but one second as 7 : 5. If the distance travelled by a freely falling body in the last second of its journey is equal to the distance travelled in the first 2s, the time of descent If a freely falling body travels in the last second a distance equal to the distance traveled by it in the first 3 seconds. 2 m/s (c) 29. It is given in the problem that the body covers half of the total distance in the last second of the fall of the body. May 7, 2025 · A body is falling from a height *h* and it travels a distance of *• {h/2}* during the last second of its motion. Find the entire distance traveled by the body. cppsmauxqkdtewnrkgswvezgsjnp4yfj82uosofqavyvfn3p